Rearrange Words In A Sentence

문제

• First letter is in upper case.

• Each word in text are separated by a single space.

Input: text = "Leetcode is cool"
Output: "Is cool leetcode"
Explanation:There are 3 words, "Leetcode" of length 8, "is" of length 2 and "cool" of length 4.
Output is ordered by length and the new first word starts with capital letter.

Input: text = "Keep calm and code on"
Output: "On and keep calm code"
Explanation:Output is ordered as follows:
"On" 2 letters.
"and" 3 letters.
"keep" 4 letters in case of tie order by position in original text.
"calm" 4 letters.
"code" 4 letters.

Input: text = "To be or not to be"
Output: "To be or to be not"

풀이

const arrangeWords = (text) => {
  return text
    .toLowerCase()
    .split(" ")
    .sort((a, b) => (a.length !== b.length ? a.length - b.length : 0))
    .map((val, idx) => (!idx ? val[0].toUpperCase() + val.slice(1) : val))
    .join(" ");
};
// faster than 46%

var arrangeWords = function(text) {
    let answer = '', arr = [];
    const splited = text.split(' ');
    
    splited.forEach(str => {
        const length = str.length;
        arr.push([str.toLowerCase(), length]);
    });

    arr.sort((a, b) => a[1] - b[1]);
    arr.forEach((d, i) => {
        if(i === 0) {
            answer += d[0][0].toUpperCase() + d[0].substr(1);
        }
        else {
            answer += ` ${d[0]}`
        }
    });
    return answer;
};

const arrangeWords = (text) => {
    const strings = text.split(" ").map((str) => str.toLowerCase());
        
    strings.sort((a, b) => a.length - b.length);
    
    const joined = strings.join(" ");
    
    return joined.charAt(0).toUpperCase() + joined.slice(1);
};